Django任意URL跳转漏洞（CVE 2018 14574)
Django任意URL跳转漏洞¶
在Django默认配置下，用户访问的URL的最后一位应该是以斜杠结尾，如果用户输入的URL没加斜杠，那么会默认自动帮你补上它并跳转到带斜杠的请求中。在path开头为//example.com的情况下，Django没做处理，导致浏览器认为目的地址是绝对路径，最终造成任意URL跳转漏洞。该漏洞利用条件是目标URLCONF中存在能匹配上//example.com的规则。
漏洞详情¶
影响版本：version < 2.0.8
漏洞原因：Django安装好后，当settings模块配置好了django.middleware.common.CommonMiddleware，且APPEND_SLASH为True时漏洞就会触发（这两个配置是默认存在的）。
CommonMiddleware其实是Django中的一个中间件，因为Django是用python写的，所以又可以说它是一个位于site-packages/django/middleware/common.py的一个类。Django在接受到一个请求（request）后，会先放到中间件（CommonMiddleware）中去处理，然后再通过默认的 URL 方式进行。如果设置了APPEND_SLASH=True，并且用户输入的URL没有以斜杠结尾，在urlpatterns中也匹配不到这个URL，则通过在末尾附加斜杠来形成新的URL。如果在urlpatterns中找到此新URL，则将HTTP重定向返回到此新URL。例如：
初始链接：http://your-ip:8000/test
301重定向后的链接：http://your-ip:8000/test/
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但是如果URL是这样的：http://your-ip:8000//example.com，那么程序会进入site-packages/django/middleware/common.py下执行process_request()函数：
def process_ request(self, request):
"""
Check for denied User-Agents and rewrite the URL based on
settings. APPEND_ SLASH and settings. PREPEND_ WWW
"""
# Check for denied User-Agents
if 'HTTP_ USER_ AGENT' in request.META:
for user_ agent_ regex in settings .DISALLOWED _USER_ AGENTS:
if user_ agent_ regex . search(request .META['HTTP_ USER_ AGENT']):
raise Permi ssionDenied( ' Forbidden user agent ' )
# Check for a redirect based on settings.PREPEND WWW
host = request.get host()
must_ prepend = settings.PREPEND _WWW and host and not host . startswith( ' www.' )
redirect_ url = ( '%s:/ /WWw.%s' % ( request. scheme, host)) if must_ prepend else''
# Check if a slash should be appended
if self.should_ redirect_with_slash(request):
path = self.get_fu11_path_with_slash(request)
else :
path = request.get _fu11_ _path()
# Return a redirect if necessary
if redirect_ _url or path != request.get_ full_ path():
redirect_ url += path
return self .response_ redirect_ class(redirect_ url)
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可以看到，上面的程序会进入get_full_path_with_slash()函数：
# Check if a slash should be appended
if self.should_ redirect_with_slash(request):
path = self.get_fu11_path_with_slash(request)
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分析一下get_full_path_with_slash()函数：
def get_full_path_with_slash(self, request):
Return the full path of the request with a trailing sLash appended.
Raise a RuntimeError if settings.DEBUG is True and request. method is
POST, PUT, or PATCH.
new path = request.get_full_path(force_append_slash=True )
if settings . DEBUG and request . method in ( 'POST', 'PUT', 'PATCH' ):
raise RuntimeError
"You called this URL via %( method)s, but the URL doesn't end
"in a slash and you have APPEND_ SLASH set. Django can't'
"redirect to the slash URL while maintaining %( method)s data .
"Change your form to point to %(url)s (note the trailing ”
"slash),
or set APPEND_SLASH=False in your Django settings." % {
method ' : request . method，
url': request.get_host() + new_ path,
}
return new_ path
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其实作用就是给path末尾加上斜杠，也就是返回一个//example.com/
接着进入response_redirect_class函数,它是HTTP跳转的一个基类：
# Return a redirect if necessary
if redirect_ url or path != request. get_ ful1_ path():
redirect_ _url += path
return self. response redirect_ class (redirect_ ur 1)
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以//开头的外部URL将由浏览器翻译为协议、绝对URL
再往后有对协议的检查，但是scheme根本就不存在，所以会跳过这个判断：
class HttpResponseRedirectBase (HttpResponse):
allowed_ schemes = [ 'http', 'https', 'ftp']
def init__ (self, redirect to, *args, **kwargs):
super( )._ init_ ( *args, **kwargs )
self['Location'] = iri_ to_ uri(redirect_ tq)
parsed = urlparse(str(redirect_ to))
if parsed. scheme and parsed. scheme not in self . allowed_ schemes:
raise DisallowedRedirect("Unsafe redirect to URL with protocol '%s'" % parsed. scheme )
url = property(lambda self: self[ 'Location'])
def_ repr_ (self):
return '<%(c1s)s status_ code=%( status_ code )d%( content_ type)s, ur1="%(ur1)s">' % {
cls': self._ class__ ._ name___ ,
status_ code' : self. status_ code ,
content_ type': self.. content_ type_ for repr,
url' : self .ur1,
}
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接着可以看到正常的301跳转
漏洞复现¶
进入环境
301重定向后尾巴加了斜杠 
添加//www.baidu.com后实现了页面的跳转
成功跳转 